>>5
I said ``/r/ the Unicode REASON name plate posted here some time ago.''.
Name:
Anonymous2008-06-14 19:55
┌─────────────────────────────────────────────────┒
│ ◕ ◕ ┃
│ REASON ┃
│ Version 1.0B7 ┃
│ Gatling type 3 mm hypervelocity railgun system ┃
│ Ng Security Industries, Inc. ┃
│ PRERELEASE VERSION-NOT FOR FIELD USE ┃
│ DO NOT TEST IN A POPULATED AREA ┃
│ -ULTIMA RATIO REGUM- ┃
│ ◕ ◕ ┃
┕━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━┛
┌─────────────────────────────────────────────────┒
│ ◕ ◕ ┃
│ REASON ┃
│ Version 1.0B7 ┃
│ Gatling type 3 mm hypervelocity railgun system ┃
│ Ng Security Industries, Inc. ┃
│ PRERELEASE VERSION-NOT FOR FIELD USE ┃
│ DO NOT TEST IN A POPULATED AREA ┃
│ -ULTIMA RATIO REGUM- ┃
│ ◕ ◕ ┃
┕━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━┛
i am a JAVA. i ahev a long doc and i make programs w/ my API. if you dont repost this comment on 10 other pages i will hax your anus tonight and make a mess of your computer and ass
>>1
How can I make this work for common lisp?
I understand in scheme it takes a function and returns a function that takes an argument and applies it to f.
In scheme
(((lambda (f) (lambda (x) (f x))) (lambda (x) (+ x 1))) 41)
But in common lisp?
Name:
Anonymous2008-06-15 22:43
(funcall ((lambda (f) (lambda (x) (funcall f x))) (lambda (x) (+ x 1))) 41)