90% of /prog/ can't write FizzBuzz

Prove me wrong

Write a program that prints the numbers from 1 to 100. But for multiples of three print "Fizz" instead of the number and for the multiples of five print "Buzz". For numbers which are multiples of both three and five print "FizzBuzz".

>>67
The fun thing about FizzBuzz (other than writing obfuscated versions) is to write versions that seem correct but aren't, present them to others and see if they spot the mistake.

(define l '((3 . "fizz") (5 . "buzz")))
(define (f l method f2 n m)
  (if (<= n m)
      (begin
      (check l method f2 n #f)
      (f l method f2 (+ n 1) m))))

(define (check l method f n x)
  (if (not (null? l))
      (if (method n (caar l))
          (begin
            (f (cdar l))
            (check (cdr l) method f n #t))
          (check (cdr l) method f n #f))
      (if (not x) (f n))))

(define (fizzbuzz n)
  (f l (lambda (a b) (= (remainder a b) 0)) (lambda (x) (display x)) 1 n))

int n = 1;
while( n <= 100 )
{
    if( !( n % 3 ) && !( n % 5 ) )
        printf( "FizzBuzz" );
    else
    if( !( n % 3 ) )
        printf( "Fizz" );
    else
    if( !( n % 5 ) )
        printf( "Buzz" );
    else
        printf( "%d", n );
   
    n++;
}

// FizzBuzz v2.0
short n = 1;
while( n <= 100 )
{
    short n0 = n;
    if( !( n % 3 ) )
    {
        n0 = 0;
        printf( "Fizz" );
    }
    if( !( n % 5 ) )
    {
        n0 = 0;
        printf( "Buzz" );
    }
    if( n0 )
        printf( "%d", n );
    n++;
}

#!/usr/bin/perl
$fizzbuzz = 'fizzbuzz.pl';
open FIZZBUZZ, '>', $fizzbuzz or die "Well fuck you...\n";
print FIZZBUZZ "#!/usr/bin/perl\n";
foreach $i (1..100)
{
    print FIZZBUZZ "(!($i % 3) && !($i % 5)) ? print \"FizzBuzz\\n\" : !($i % 3) ? print \"Fizz\\n\" : !($i % 5) ? print \"Buzz\\n\" : print \"$i\\n\";\n";
}
close FIZZBUZZ;
chmod 0700, $fizzbuzz;

>>76
The first one looks like perl, but what the fuck are the other two?

>>77
This isn't supposed to be hard. This is a basic interview smoke test to check if a person is capable of programming.

Toy language lovers, however, enjoy taking simple problems (like the factorial) and rewriting it in clever ways or obscure languages.

>>85
?code Forth some dat is lawd Oh

>>87
That ain't no Forth code. I believe it's either Factor or Joy.

for (int i=1;i<=100;i++) {
 if(i%15==0) {
  System.out.println("FizzBuzz");
 } else if (i%5==0) {
  System.out.println("Buzz");
 } else if (i%3==0) {
  System.out.println("Fizz");
 } else {
  System.out.println(i);
 }
}

java.

hax my anus
my anus hax
anus hax my

>>90
I hope you die.

>>91
Stop replying to these post, god-damn.

>>91
I hope you hax my anus.

>>92
Stop replying to these post, god-damn.

#include <iostream>

using namespace std;

int main ()
{
        bool mod = 1;
        for ( int i  = 1; i < 101; i++)
        {
                if ( i % 3 == 0)
                { 
                        cout << "Fizz";
                        mod = 0;
                } 
                if ( i % 5 == 0)
                { 
                        cout << "Buzz";
                        mod = 0;
                } 
                if (mod)
                        cout << i;
                mod = 1;
                cout << endl;
        }
        return 0;
}


using namespace boost;
using namespace std;

foreach(
  make_counting_iterator<int>(0),
  make_counting_iterator<int>(101),
  (
    if_(_1 % 15 == 0) [
      cout << constant("FIZZBUZZ\n")
    ].else_[
      if_(_1 % 5 == 0) [
        cout << constant("BUZZ\n")
      ].else_[
        if_(_1 % 3 == 0) [
          cout << constant("FIZZ\n")
        ].else_[
          cout << _1 << "\n"
        ] ] ] ) );

>>76
Good sir, did you write that Perl solution? Because it looks like one of my programs.

>>97
I did.
hax my anus

99 GET

100 GET FAGGOTS

I counted 25 code-snippets-that-look-like-FizzBuzz. Obviously it's innacurate, but who cares.

So, 75% of /prog/ can't write FizzBuzz. At least it's not 90%

>>101
Or people just don't want to write fizzbuzz in every post.

            for (int i = 0; i < 100; i++)
            {
                if(i % 3 == 0)
                    Console.Write("Fizz");
                if(i % 5 == 0)
                    Console.Write("Buzz");
                else if((i % 5) * (i % 3) != 0)
                    Console.Write(i);
                Console.WriteLine();
            }
            Console.ReadKey();

Not a perfect solution, as numbers that are multiples of 3 and not of 5, gets evaluated twice. Apart from that it prints the desired result.

For numbers which are multiples of both three and five print "FizzBuzz".

>>104
Well yeah... it's an If If, not an If Else If. Both If's will be determined for each number and for those numbers where both are true both Fizz and Buzz will be printed

>>105
I did not understand what you meant, but you have made me realise that the blocks in >>103 are quite weird.

So I started thinking, what about controlling the output cache? If there's something, print \n, if not, print i. I wouldn't consider implementing that in java, though.

anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus anus

So for 15, should it print Fizz, Buzz and FizzBuzz or just FizzBuzz?

>>107
you forgot the "hax my" part

Mine is fizz.

>>109
Sorry.

hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus hax my anus

>>85,87-88
the third one is factor.
the second one is false. it's funny how short it is, even though the language lacks a modulus operator.

>>95,96
stl = fail

for x in range(1,101):
    print ((not x%3)  and x%5 and 'fizz') or ((not x%5) and x%3 and 'buzz') or ( ((not x%5) and (not x%3)) and 'fizzbuzz') or x

>>114
Still includes some fioc. Try this one:

print '\n'.join([str(((not x%3)  and x%5 and 'fizz') or ((not x%5) and x%3 and 'buzz') or ( ((not x%5) and (not x%3)) and 'fizzbuzz') or x) for x in range(1, 101)])

>>57
fags

but srsly, if python programmers could stop abusing the boolean operators in general that would be GREAT, thanks

>>116
Those are logical operators.

>>117
http://docs.python.org/ref/Booleans.html

but regardless of what you call them, it seems to be trendy to use them to make python code fucking unreadable

It's incredible how much fail can accumulate in just one thread

>>119
It's incredible how much fail can accumulate in just one board