Boolean Algebra; Help!

#include <iostream>

using namespace std;

int main()

{
   
    float number;
   number = 9;
    if (number == 2 || 3)
    {cout<<"\n\nRight!";}
    else{cout<<"Wrong";}
    cin.get();
   
}


This script (in my understnding) should display "Wrong", it actually displays "Right"

Help?

You are testing if number == 2, then if 3, so it will always be true as 3 is true.
Also, READ SICP

Since nobody else has actually included what the right code is, here you go...

if (number == 2 || number == 3)

The operators == || && all take two numbers and produce either 0 or 1.

== produces 1 if the two numbers are equal and 0 otherwise.
|| produces 0 if both numbers are 0 and 1 otherwise.
&& produces 1 if both numbers are 1 and 0 otherwise.

Hence, (number == 2 || 3) can be read as (number == 2) || 3, regardless of what the left side of || is, the right side is 3, which is not 0, and so the || returns 1 (true).

>>13

Thanks, appreciate it.

It's people like you that mean the more cerebral boards aren't degraded into /b/ replicates.