LISP [part λ f x. f (f x)]
Name:
Anonymous
2008-01-31 8:38
LISP
Name:
Anonymous
2008-02-19 19:38
Name:
Anonymous
2008-02-20 7:16
LISP LISP LISP
Name:
Anonymous
2008-02-20 9:30
LISP LIPS LSIP LSPI LPIS LPSI ILSP ILPS ISLP ISPL IPLS IPSL SLIP SLPI SILP SIPL SPLI SPIL PLIS PLSI PILS PISL PSLI PSIL
Name:
Anonymous
2008-02-20 9:55
>>763
Done using
[[a,b,c,d] | a <- ['L', 'I', 'S', 'P'], b <- ['L', 'I', 'S', 'P'], c <- ['L', 'I', 'S', 'P'], d <- ['L', 'I', 'S', 'P']]-mode
Name:
Anonymous
2008-02-20 9:57
Name:
Anonymous
2008-02-20 10:01
Wait, these are permutations with repetition. How do I permute without repetition?
Name:
Anonymous
2008-02-20 10:06
Name:
Anonymous
2008-02-20 10:21
>>764
actually no. it's from a c program i wrote that prints permutations.
Name:
Anonymous
2008-02-20 10:22
Name:
Anonymous
2008-02-20 10:28
>>768
Actually, no, it was an one-liner from standard Haskell library that prints permutations.
Name:
Anonymous
2008-02-20 10:29
Name:
Anonymous
2008-02-20 10:31
LISP
Name:
Anonymous
2008-02-20 10:32
LISP
Name:
Anonymous
2008-02-20 10:33
LISP
Name:
Anonymous
2008-02-20 10:40
>>771
Pipe the output into
uniq.
Name:
Anonymous
2008-02-20 10:54
>>775
That ain't no Haskell then.
Name:
Anonymous
2008-02-20 10:54
Oh, also chmod allow all GET.
Name:
Anonymous
2008-02-20 11:16
>>777
$ chmod allow all
chmod: invalid mode: `allow'
Try `chmod --help' for more information.
Name:
Anonymous
2008-02-20 12:12
>>778
$ chmod allow all
chmod: invalid mode: `allow'
Try `chmod --help' for more information.
chmod: invalid mode: `allow'
mode: `allow'
allow-mode
Name:
Anonymous
2008-02-20 12:16
chmod: invalid mode: `allow'
invalid mode: `allow'
`allow'
`'
WRYYYYYYYYYYYYYYYYYY
Name:
Anonymous
2008-02-20 12:17
>>780
What's the matter with char.properQuotes?
Name:
Anonymous
2008-02-20 12:23
>>766
lexPerms [] = [[]]
lexPerms l = concatMap (\(x,y) -> map (x:) $ lexPerms y) $ cp [] l where
cp p (x:xs) = (x,p++xs) : cp (p++[x]) xs
cp p _ = []
Name:
Anonymous
2008-02-20 12:53
>>782
I don't understand ;_;
Name:
Anonymous
2008-02-20 13:08
Name:
Anonymous
2008-02-20 13:10
>>784
Please explain the function.
Name:
Anonymous
2008-02-20 13:49
LISP
Name:
Anonymous
2008-02-20 17:31
LISP
Name:
Anonymous
2008-02-20 19:47
Name:
Anonymous
2008-02-20 19:49
Therefore, lisp
Name:
Anonymous
2008-02-20 19:50
AD LISP
Name:
Anonymous
2008-02-20 19:51
LISP >>= LISP -> LISP
Name:
Anonymous
2008-02-20 19:54
LISP
Name:
Anonymous
2008-02-20 23:26
L=P
Name:
Anonymous
2008-02-21 1:22
LISP
Name:
Anonymous
2008-02-21 2:02
>>791
LISP lisp => lisp -> lisp
Name:
Anonymous
2008-02-21 4:00
I AM SAGING THIS THREAD FOR THE FOLLOWING REASONS:
Name:
Anonymous
2008-02-21 4:10
Name:
Anonymous
2008-02-21 4:24
>>1-797 is the same person and we have been trolled constantly.
Name:
Anonymous
2008-02-21 4:28
LISP
Name:
Anonymous
2008-02-21 4:29
LISP
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