Divisible by 3 or 5, in lisp

(lambda (n) (or (= 0 (mod n 3)) (= 0 (mod n 5))))

how on earth do you write this in lisp, I mean better than I have here.. surely it must be possible?

Rube Goldberg devices are definitely acceptable if it makes the final code better.. hope you have some ideas /prog/

: divisible_by_any? ( n seq -- ? ) [ mod ] map-with product zero? ;
: divisible_by_3_or_5? ( n -- ? ) { 3 5 } divisible_by_any ;