Divisible by 3 or 5, in lisp

(lambda (n) (or (= 0 (mod n 3)) (= 0 (mod n 5))))

how on earth do you write this in lisp, I mean better than I have here.. surely it must be possible?

Rube Goldberg devices are definitely acceptable if it makes the final code better.. hope you have some ideas /prog/

yeah i dont know lisp or anything but this thread is hilarious i mean what the fuck is >>21 even supposed to mean and how does it relate to finding if numbers are evenly divisible by 3 or 5