Var Args are funky

When I did a return from va_arg(args, void *), it always seems to return null even though there are more arguments remaining. In this case, the arg list is filled with vars that need to be free'd prior to exiting the program. Anyone know why such an unsightly approach is needed?

int cp_error(const char *msg, int varc, ...) {
    int varg = 0;
    va_list args;

    if (varc > 0) {
        varg = 1;
        va_start(args, msg);
    }

    while (--varc >= 0) {
        va_arg(args, void *);
        free( (void *) *((char **) args) );
    }

    if (varg) {
        va_end(args);
    }

    fprintf(stdout, "%s\n", msg);

    return 0;
}

>>14
Perhaps you're interpreting "my way" wrong. I'd post correct code, but I again have no clue how to use world4ch's code tags.