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How I deuglified my function?

Name: Anonymous 2007-03-21 15:10 ID:4itzFHZ3

xam :: a -> a -> b

xam x y = foo (bar x) (bar y) (baz x) (baz y)

Name: Anonymous 2007-03-22 7:54 ID:T6QAOBUR

I don't know Lisp, but I believe this would be equivalent:

xam = lambda *x: return foo(map(bar, x) + map(baz,x))

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