How I deuglified my function?

xam :: a -> a -> b
xam x y = foo (bar x) (bar y) (baz x) (baz y)

>>11
Not so much in a purely functional language.

They are probably pretty hard to use in Haskell though, I found an implementation, but it was several levels beyond my understanding.

http://okmij.org/ftp/Haskell/vararg-fn.lhs